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What are the dimensions of the quantity 1 beinglength andg the acceleration due tothe gravity ? |
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Answer» Explanation:We have to FIND the dimensions of the quantity L\TIMES \sqrt{l/G} We KNOW that Dimension of length l = [L] Dimensions of acceleration due to gravity g = [LT^{-2}] Therefore, dimensions of l × √(l/g) =[L]\times\sqrt{[L]/[LT^{-2}]} =[L]\times\sqrt{[T^{2}]} =[L]\times{[T^{2}]^{1/2} =[L][T] Therefore the dimensions of l × √(l/g) are [L][T] Hope this helps. |
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