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What are [i] the highest and [ii] the lowest total resistances which can be secured by combinations of four coils of resistances 4Omega,8Omega,12Omegaand24Omega? |
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Answer» SOLUTION :i] For highest RESISTANCE, resistors are CONNECTED in series. `R_(s)=R_(1)+R_(2)+R_(3)+R_(4)=4+8+12+24=48Omega` II] For lowest resistance, resistors are connected in parallel. `1/R_(p)=1/4+1/8+1/12+1/24=(6+3+2+1)/24=12/24=1/2`. THEREFORE, `R_(p)=2Omega`. |
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