1.

What ammount of dioxygen (in gram) contains 1.8 xx 10^23 molecules ?

Answer»

`0.960`
`96.0`
`0.960`
`9.60`

Solution :`6.022xx10^(23)` moleculesare present in 32 g of `O_(2)`
` :. "" 1.8 xx10^(22)`MOLECULES will be present in
`32/(6.022 xx10^(23))xx1.8 xx10^(22) g`
` = 0.960` g of `O_(2)`


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