Weight of 112 mL of oxygen at NTP on liquefaction would be _______. (A) 0.32 g (B) 0.64 g (C) 0.16 g (D) 0.96 g

Weight of 112 mL of oxygen at NTP on liquefaction would be _______.

1.	Weight of 112 mL of oxygen at NTP on liquefaction would be _______. (A) 0.32 g (B) 0.64 g (C) 0.16 g (D) 0.96 g
Answer» C)0.16g of oxygen is REQUIRED.Explanation: Firstly calculate moles from equationmoles= volume of gas in litre/ 22.4moles=0.112/22.4moles=0.005Now compare moles with other equation of molemole = required mass/molecular mass0.005=required mass of oxygen /32required mass of O2= 0.005*32=0.16ghope you LIKE it!!Mark as BRAINLIEST