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Water rises to a height of `10 cm` in a capillary tube and mercury falls to a depth of `3.42 cm` in the same capillary tube. If the density of mercury is `13.6 g//c.c.` and the angles of contact for mercury and for water are `135^@` and `0^@`, respectively, the ratio of surface tension for water and mercury isA. `1 : 0.15 `B. `1 : 3`C. `1 : 6.5`D. `1.5 : 1` |
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Answer» `h=(2Tcostheta)/(rrhog)` or `s=(hrrhog)/(2costheta)` or `S prop(hrho)/(costheta)` `(S_(w))/(S_(Hg))=(h_(1))/(h_(2))xx(costheta)/(costheta_(1))xx(rho_(1))/(rho_(2))` Putting the values, we obtain `1 : 6.5` |
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