Water is flowing through a horizontal tube of length 0.25 m and radius4xx 10 ^(-4) m under a constant pressure head of 0.2 m of water, at the rate of 5 xx 10 ^(-6) m^(3) per minutre . Calculate the coefficient of visosity of water. Density of water = 1000 kg m^(-3)

Water is flowing through a horizontal tube of length 0.25 m and radius

1.	Water is flowing through a horizontal tube of length 0.25 m and radius4xx 10 ^(-4) m under a constant pressure head of 0.2 m of water, at the rate of 5 xx 10 ^(-6) m^(3) per minutre . Calculate the coefficient of visosity of water. Density of water = 1000 kg m^(-3)
Answer» Solution :` "" l = 0.25 m, r- 4 xx 10 ^(-4) m ` ` ""P= h rho g =0.2 m " ofwater"= 0.2 xx 10 ^(3)xx 9.8 Pa` Volume ` V = 5 xx 10 ^(-6)m^(3)` ` "" t= ` one minute = 60S ` eta = ? ` ` Q = ( V)/(t)= (pi P r^(4))/( 8 eta l) ` ` eta = ( pi h rho g r^(4) t)/( gl V) ` `= (3.14 xx 0.2 xx 10 ^(-3)xx 9.8 xx ( 4 xx 10 ^(-4) ) ^(4) xx 60 )/( 8 xx 0.25 xx 5 xx 10 ^(-6)) ` `= 0 .000945 N s m^(-2)`