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Water is flowing through a 200 mm diameter pipe with coefficient of friction f = 0.04. The shear stress at a point 40 mm from the pipe axis is 0.00981 n/cm2. The shear stress at the pipe wall will be |
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Answer» diameter of pipe , d = 200mm radius of pipe , r = 100mm COEFFICIENT of friction, f = 0.04 shear STRESS at a point r = 40mm , = 0.00981 N/cm²we have to find shear stress at the pipe wall.Let shear stress at the pipe wall is first of all, we have to find where is viscous or not . we know, the flow will be viscous if Reynolds's NUMBER less than 2000.use Re = 16/0.04 = 400 < 2000this means flow is viscous. now shear stress in case of viscous flow through a pipe is given by, but is constant across a section as There is no variation of x so, there is no variation of p.so, e.g., so, = 100/40 × 0.00981 =0.0245 N/cm² |
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