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Water in a rectangular reservoir having base 80 m by 60 m is 6.5 m deep. In what time can the water be emptied by a pipe of which the cross-section is a square of side 20 cm, if the water runs through the pipe at the rate of 15 km/hr. |
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Answer» Given, Dimension of rectangular reservoir = 80m × 60m Depth of water in reservoir = 6.5 m Side of square pipe = 20cm Rate of flow of water through pipe = 15 km/h Volume of reservoir = 80 × 60 × 6.5 m3 Volume of pipe = \(\cfrac{20}{100}\times15000\) m3 Let reservoir be emptied in t hours \(=\cfrac{20}{100}\times\cfrac{20}{100}\times15000\times t\) = 80 x 60 x 6.5 = t = \(\cfrac{80\times60\times6.5\times100\times100}{20\times20\times15000}\) = 52 hours |
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