Water in a cylindrical tank of diameter 4m and height 10mcylindrical p

1.	Water in a cylindrical tank of diameter 4m and height 10mcylindrical pipe of diameter 10 cm at the rate of 2.5 Km/hr. Hoto empty the half of the tank? Assume that the tank is full of water to begin withis released throughaw much time will t take
Answer» Diameter of the cylindrical tank = 4 m radius of the cylindrical tank = 2 m height of the tank = 10 m Diameter of the cylindrical pipe = 10 cm radius of the cylindrical pipe = 10/2 = 5 cm = 5/100 m speed of water = 2.5 km/hr 1000 m = 1 km = 2.5 x 1000 = 2500 m/hr Volume of water discharged from the cylindrical pipe = (1/2) Volume of cylindrical tank Area of cross sectionxtimexspeed = (1/2)Πr² h Πr²xtimexspeed = (1/2)Πr² h (5/100)²xtimex2500 = (1/2)(2)² (10) (5/100)x(5/100)xtimex2500 = (1/2)x(2)x2x(10) Time =2x10x(100/5)x(100/5)x(1/2500) Time =80/25 = 3.2 hour 1 hour = 60 minute = 192 minute = 180 + 12 3 hour and 12 minute Therefore time taken to empty the half of the tank is 3 hour and 12 minute

Water in a cylindrical tank of diameter 4m and height 10mcylindrical pipe of diameter 10 cm at the rate of 2.5 Km/hr. Hoto empty the half of the tank? Assume that the tank is full of water to begin withis released throughaw much time will t take

Answer»

Diameter of the cylindrical tank = 4 m

radius of the cylindrical tank = 2 m

height of the tank = 10 m

Diameter of the cylindrical pipe = 10 cm

radius of the cylindrical pipe = 10/2 = 5 cm

= 5/100 m

speed of water = 2.5 km/hr

1000 m = 1 km

= 2.5 x 1000

= 2500 m/hr

Volume of water discharged from

the cylindrical pipe = (1/2) Volume of cylindrical tank

Area of cross sectionxtimexspeed = (1/2)Πr² h

Πr²xtimexspeed = (1/2)Πr² h

(5/100)²xtimex2500 = (1/2)(2)² (10)

(5/100)x(5/100)xtimex2500 = (1/2)x(2)x2x(10)

Time =2x10x(100/5)x(100/5)x(1/2500)

Time =80/25

= 3.2 hour

1 hour = 60 minute

= 192 minute

= 180 + 12

3 hour and 12 minute

Therefore time taken to empty the half of the tank is 3 hour and 12 minute