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Water in a canal, 30dm wide and 12dm deep, is flowing with a velocity of 20km per hour. How much area will it irrigate, if 9cm of standing water is desired? |
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Answer» We know that water in a canal forms a cuboid The dimensions are Breadth = 30dm = 3m Height = 12dm = 1.2m We know that Length = distance covered by water in 3 minutes = velocity of water in m/hr × time in hours By substituting the values Length = 20000 × (30/60) So we get Length = 10000m We know that Volume of water flown in 30 minutes = l × b × h By substituting the values Volume of water flown in 30 minutes = 10000 × 3 × 1.2 = 36000 m3 Consider A m2 as the area irrigated So we get A × (9/100) = 36000 On further calculation A = 400000 m2 Therefore, the area to be irrigated is 400000 m2. |
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