Water in a canal 30 dm wide and 12 dm deep, is flowing with a velocity

1.	Water in a canal 30 dm wide and 12 dm deep, is flowing with a velocity of 100 km per hour. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired?
Answer» Given, Width of canal = 30 dm = 3m Depth of canal = 12 dm = 1.2 m Velocity of flow = 100 km/h Length of cuboid thus formed = distance travelled by water in 30 minute at speed 100km/h \(=100\times\cfrac{30}{60}\) = 50 km = 50000m Volume of water = 50000 × 3 × 1.2 m³ Water accumulated in field forms a cuboid of base area equals to area of field and height = \(\cfrac{8}{100}m\) = hence, area of field = \(\cfrac{5000\times3\times1.2\times100}8\) = 2250000m²

Water in a canal 30 dm wide and 12 dm deep, is flowing with a velocity of 100 km per hour. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired?

Answer»

Given,

Width of canal = 30 dm = 3m

Depth of canal = 12 dm = 1.2 m

Velocity of flow = 100 km/h

Length of cuboid thus formed = distance travelled by water in 30 minute at speed 100km/h

\(=100\times\cfrac{30}{60}\) = 50 km = 50000m

Volume of water = 50000 × 3 × 1.2 m³

Water accumulated in field forms a cuboid of base area equals to area of field and height = \(\cfrac{8}{100}m\)

= hence, area of field = \(\cfrac{5000\times3\times1.2\times100}8\) = 2250000m²