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Water in a canal 1.5 m wide and 6 m deep is flowing with a speed of 10 km/hr. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired? |
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Answer» Speed of flowing water = 10 km/hr In 30 minutes length of flowing water =10 × \(\frac{30}{60}\) km = 5 km = 5000 m Volume of flowing water in 30 minutes = 5000 × width × depth Width of canal = 1.5 m Depth of canal = 6 m Volume of canal = 5000 × 1.5 × 6 m3 = 45000 m3 Irrigated area in 30 minutes if 8 cm of flowing water is required = \(\frac{45000}{0.08}\) = 562500 m2 |
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