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Water flows through the tube shown in figure. The areas of cross section of the wide and the narrow portions of the tube are `5cm^2 and 2cm^2` respectively. The rate of flow of water through the tube is `500 cm^3s^-1` . Find the difference of mercury levels in the U-tube. |
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Answer» Correct Answer - A::C Given Rate of Glow `=500cm^3/sec` `rarrv_A=(500/5)=100cm/sec` `V_Aa_A=V_Ba_B` `rarr v_A/v_B=a_B/a_A=2/5` `rarr 5v_A=2v_B` `rarr v_B=(5/2)v_A`…………i `rarr 1/2rhov_A^2+rhogh_A+pA=1/2 rhov_B^2+rhogh_B+p_B` `rarr p_A-p_B=1/2[p(v_B^2-v_A^2)]` `rarr hxx13.6xx980=1/2xx1xx21/4(100)^2` [Using i] [because `p_A-p_B=?]` `rarr h=(21xx(100)^2)/(2xx13.6xx980xx4)` `=1.969cm` |
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