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Water flows through a tube shown in figure. The areas of cross section at A and B are `1cm^2 and 0.5 cm^2` respectively. The height difference between A and B is 5m. If the speed of water at A is 10 `cms^-1` find a the speed at B and b the difference in pressures at A and B. |
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Answer» Correct Answer - A::B::C::D a. `vecV_Axxa_A=vecV_B=a_B` `rarr 10xx1=vecV_Bxx0.5` `rarr vecV_B=20cm/sec` `b. 1/2rhov_A^2+rhogh_A+p_A` `=1/2rhov_B^2+rhogh_A+p_B` `rarr p_B-p_A=1/2rho(v_A^2-v_B^2)+rhog(h_A-h_B)` `=1/2xx1(100-400)+1xx1000(5.0)` `=-150+5000=4850Dyne/cm^2` `485N/m^2` |
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