Water flows through a horizontal tube as shown in figure. If the difference of heights of water colun in the vertical tubes is 2 cm and the area of cross section at A and B are `4cm^2 and 2cm^2` respectively, find the rate of flow of water across any section.

Water flows through a horizontal tube as shown in figure. If the diffe

1.	Water flows through a horizontal tube as shown in figure. If the difference of heights of water colun in the vertical tubes is 2 cm and the area of cross section at A and B are `4cm^2 and 2cm^2` respectively, find the rate of flow of water across any section.
Answer» Correct Answer - A::C::D v_A=a_A=v_Bxxa_B` `rarr v_Axx4=v_Bxx2` `rarr v_B=2v_A`…i `-Again `1/2rhov_A^2+rhogh_A+p_A=1/2rhov+B^2+rhogh_B+p_B` `rarr 1/2rhov_A^2+p_A=1/2rho(v_B^2-v_A^2)` `rarr p_A-p_B=1/2rho(v_b^2-v_A^2)` `=1/2xx1xx(4v_A^2-v_A^2)` `rarr 2xx1xx1000=1/2xx1x3v_A^2` =[p_A-p_B=2cm` of water column `=2xx1xx1000dyne/cm^2]` `rarrv_A^2=sqrt(4000/3)=36.51cm/sec` `So, rate of flow =V_aa_A=36.50xx4` `=146cm^3/sec`

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Water flows through a horizontal tube as shown in figure. If the difference of heights of water colun in the vertical tubes is 2 cm and the area of cross section at A and B are `4cm^2 and 2cm^2` respectively, find the rate of flow of water across any section.

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