Water flows out through a circular pipe whose internal diameter is 2 c

1.	Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6 metres per second into a cylindrical tank, the radius of whose base is 60 cm. Find the rise in the level of water in 30 minutes?
Answer» Given, internal diameter of pipe = 2 cm internal radius of pipe = \(\frac{2}{2}\) = 1 cm rate of flow of water = 6 m/s = 600 cm/s radius of base of cylindrical tank = 60 cm so, rise in height in cylindrical tank = \(\frac{rate\,of\,flow\,of\,water\times total\,time\times volume\,of\,pipe}{volume\,of\,cylinderical\,tank}\) = \(\frac{600\times 30\times 60\times π\times 1\times 1}{π\times 60\times 60}\) = 300 cm = 3 m

Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6 metres per second into a cylindrical tank, the radius of whose base is 60 cm. Find the rise in the level of water in 30 minutes?

Answer»

Given,

internal diameter of pipe = 2 cm

internal radius of pipe = \(\frac{2}{2}\) = 1 cm

rate of flow of water = 6 m/s = 600 cm/s

radius of base of cylindrical tank = 60 cm

so,

rise in height in cylindrical tank = \(\frac{rate\,of\,flow\,of\,water\times total\,time\times volume\,of\,pipe}{volume\,of\,cylinderical\,tank}\)

= \(\frac{600\times 30\times 60\times π\times 1\times 1}{π\times 60\times 60}\) = 300 cm = 3 m