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Water flows along horizontal pipe whose cross-section is not constant. The pressure is 1 cm of Hg, where the veloecity is 35 cm/s . At a point where the velocity is 65cm/s then pressure will beA. `0.89 cm of Hg`B. `89 cm of Hg`C. `0.5 cm of Hg`D. `1 cm of Hg` |
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Answer» (a) In horizontal pipe, `p_(1)+(1)/(2)rhov_(1)^(2)=o_(2)+(1)/(2)rhov_(2)^(2) " " ....(i)` Here, " " `p_(1)=rho_(m)gh_(1)=13600xx9.8xx10^(-2)` `p_(2)13600xx9.8xxh` `rho=1000 kg//m^(3)` `v_(1)=35xx10^(-2)m//s` `v_(2)=65xx10^(-2)m//s` `:.` From Eq.(ii) , we get `13600xx9.8xx10^(-2)+(1)/(2)xx1000xx(0.35)^(2)` `=13600xx9.8xxh+(1)/(2)xx1000xx(0.65)^(2)` After solving `0.89` cn of Hg |
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