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Water falls from a tap with `A_(0)=4 m^(2)`, `A=1 m^(2)` and h=2 m, then velocity v is A. `2.5 ms^(-1)`B. `6.5 ms^(-1)`C. `4.5 ms^(-1)`D. `1.5 ms^(-1)` |
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Answer» Correct Answer - B Given, `(v^(2))/(2g)=h=10 cm` `therefore " " v=sqrt(2gh)=sqrt(2xx10xx0.1)=sqrt(2) ms^(-1)` |
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