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. Water drops fall from a tap of height 1.6m at regular intervals. If the first droptouches the ground. 5th drop detaches from the tap. Then time taken by the firstdrop to reach the ground isa) 0.75sb) 0.59sc) 0.57sd) 0.55s |
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Answer» given the height = 1.6m. and since the water drop detaches from tap. so the initial velocity ia 0. no using Newton's second formula of motion.s= ut + 1/2gt² , where s= 1.6m , u= 0 , and g= 10m/s². so 1.6=0 + 1/2×10×t².=> t² = 1.6× 2/10. => t²= 0.32=> t = √0.32. = 0.5656secs the answer would be C = 0.57secs |
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