Water drips from a tap at a rate of 4 drops every 3 seconds .Volume of

1.	Water drips from a tap at a rate of 4 drops every 3 seconds .Volume of one drop of water is 0.4 cubic cm. The dripped water is collected in a cylindrical vessel.The outer diameter and uniform thickness of this vessel is 10 cm and 1 cm respectively. How many minutes will be required to fill the vessel completely if it's height is 70 cm?
Answer» Total minute to fill vessel = 109.95 minute. Given: Water drips from a tap at a rate of 4 drops every 3 seconds . Volume of one drop of water is 0.4 cubic cm. The outer diameter of this vessel is 10 cm. Uniform thickness of this vessel is 1 cm. Height of this vessel is 70 cm. Find: How many minutes will be required to fill the vessel completely. Explanation: Inside diameter of the vessel is 2 times less than thickens of the vessel because of both side thickness Inside diameter of the vessel = 10 - (2×1) =8 cm. Volume of vessel = $\frac{\pi }{4}$ ×(Inside diameter) ² × Height = $\frac{\pi }{4}$ × 8² × 70 =3518.58 cm³ 4 drops every 3 seconds and one drop =0.4 cm³ Therefore 4 drop = 4 × 0.4 = 1.6 cm³ for 3 second. Therefore for 1 minutes total volume fill will be =1.6 × $\frac{60}{3}$ = 32 cm³ Total minute to fill vessel = $\frac{3518.58}{32}$ = 109.95 minute. To learn more... 1 But the formula for power is work/time and work is a vector quantity brainly.in/question/12116446 2 Lesson name is problems on time and work 1)'A'can do a work in 10 DAYS and 'B' can do the same work in 16 days . with the help of C ,they do the work in 4 days only.in how many days 'C' can do the work alone? answer = 11 × 3/7 days brainly.in/question/3032942

Water drips from a tap at a rate of 4 drops every 3 seconds .Volume of one drop of water is 0.4 cubic cm. The dripped water is collected in a cylindrical vessel.The outer diameter and uniform thickness of this vessel is 10 cm and 1 cm respectively. How many minutes will be required to fill the vessel completely if it's height is 70 cm?

Answer»

Total minute to fill vessel = 109.95 minute.

Given:

Water drips from a tap at a rate of 4 drops every 3 seconds .
Volume of one drop of water is 0.4 cubic cm.
The outer diameter of this vessel is 10 cm.
Uniform thickness of this vessel is 1 cm.
Height of this vessel is 70 cm.

Find:

How many minutes will be required to fill the vessel completely.

Explanation:

Inside diameter of the vessel is 2 times less than thickens of the vessel because of both side thickness
Inside diameter of the vessel = 10 - (2×1)

=8 cm.

Volume of vessel = $\frac{\pi }{4}$ ×(Inside diameter) ² × Height

= $\frac{\pi }{4}$ × 8² × 70

=3518.58 cm³

4 drops every 3 seconds and one drop =0.4 cm³
Therefore 4 drop = 4 × 0.4 = 1.6 cm³ for 3 second.
Therefore for 1 minutes total volume fill will be =1.6 × $\frac{60}{3}$

= 32 cm³

Total minute to fill vessel = $\frac{3518.58}{32}$

= 109.95 minute.

To learn more...

1 But the formula for power is work/time and work is a vector quantity

brainly.in/question/12116446

2 Lesson name is problems on time and work

1)'A'can do a work in 10 DAYS and 'B' can do the same work in 16 days . with the help of C ,they do the work in 4 days only.in how many days 'C' can do the work alone?

Total minute to fill vessel = 109.95 minute.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment