1.

Want solution of question no 38 no spamming...​

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Answer:

The VALUE of x

3

+13X

2

+32x+20 is

x

3

+x

2

+12x

2

+12x+20x+20

=x

2

(x+1)+12x(x+1)+20(x+1)

=(x−1)(x

2

+12x+20)

=(x−1)(x

2

+10x+2x+20)

=(x+1)[x(x+10)+2(x+10)]

=(x+1)(x+2)(x+10)



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