wa Using sin(A+B). deduce sin²A + cos2A = 1 where A+B=90°. – InterviewSolution

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wa Using sin(A+B). deduce sin²A + cos2A = 1 where A+B=90°.

Answer»

Given: A+B=90Sin(A+B)=Sin 90=1Now, LHS=Sin²A+Cos²A =Sin²90+Cos²90 =(1²)+(0²) =1 =RHS

sorry im mistaken with the question... il post another answer

A+B=90sin(A+B)=sin90=1LHSsin^2A+cos^2A= sin^290+ cos^2 90= (1)^2+(0)^2= 1+0= 1=RHS

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