W14A force of magnitude 2N extends a spring by 0.3 m. If the spring ob

1.	W14A force of magnitude 2N extends a spring by 0.3 m. If the spring obeys Hooke law. Then, a force of 6N will extend it by :(A) 0.1 m(B) 0.3 m(C) 0.6 m(D) 0.9 m
Answer» $\Large{\blue{\underline{\underline{\mathfrak{Answer :-}}}}}$ Option D. 0.9 m is Correct. $\rule{200}{2}$ $\Large{\blue{\underline{\underline{\mathfrak{Explanation :-}}}}}$ ∴ Since, the spring obeys HOOK's law. ''This means extension produced in the spring will be directly proportional to the force. (As what said by the Hooke's law.)'' ∴ x ∝ F ∴ x = kF, where k is CONSTANT of Hooke's law. ∴ k = $\sf \dfrac{x}{F}$ ∴ k = $\sf \dfrac{0.3}{2}$ Now, when a force of 6 N is applied, then k = $\sf \dfrac{x}{6}$ Now, k being an constant will REMAINS same. ∴ $\sf \dfrac{x}{6} = \dfrac{0.3}{2}$ ∴ x = 0.9 m. *HENCE, Option (d). is correct.* $\rule{200}{2}$