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w Iftan A = , find sina colaIftan A=+COSA

Answer»

tanA=3/4; 1/sinA=1/3/5=5/3; 1/ cosA=1/4/5=5/4; 1/ sinA+1/ cosA=5/3+5/4==25/9+25/16=(25)^2/(25)=2/1=2

tanA=3/4; 1/ sinA=1/3/5=5/3; 1/ cosA=5/4; 1/ sina+1/ cosA=5/3+5/3=(25)^2/(25)=2/1

tanA=3;4sinA/cosA= 3/4sinA/3=cosA=/4=k(let)sinA= 3kcosA= 4k1/sinA+1/cosA= 1/3k+1/4k= 4k+3k/12k÷ 7k/12k= 7/12



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