व्यंजक (1 x 2x3x3x , xn के गुणनफल शू�

1.	व्यंजक (1 x 2x3x3x , xn के गुणनफल शून्यों की संख्या अंतिम म 68 है, तो 'n' का अधिकतम संभावित मान क्या होगा?(a)1(b)3(c) 5(d) 6
Answer» Step-by-step explanation: The ANSWER is 6 PLEASE MARK my answer as BRAINLIST answer

व्यंजक (1 x 2x3x3x , xn के गुणनफल शून्यों की संख्या अंतिम म 68 है, तो 'n' का अधिकतम संभावित मान क्या होगा?(a)1(b)3(c) 5(d) 6

Answer»

Step-by-step explanation:

The ANSWER is 6 PLEASE MARK my answer as BRAINLIST answer

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व्यंजक (1 x 2x3x3x , xn के गुणनफल शून्यों की संख्या अंतिम म 68 है, तो 'n' का अधिकतम संभावित मान क्या होगा?(a)1(b)3(c) 5(d) 6​

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व्यंजक (1 x 2x3x3x , xn के गुणनफल शून्यों की संख्या अंतिम म 68 है, तो 'n' का अधिकतम संभावित मान क्या होगा?(a)1(b)3(c) 5(d) 6