Volume occupied by the gas at stp of 30g of nitrogen(iv) oxide

1.	Volume occupied by the gas at stp of 30g of nitrogen(iv) oxide
Answer» Explanation: NO2 is the OXIDE with nitrogen in 4 oxidation state MASS given is 30 MOLARMASS is 14+ 162 = 46 no of moless is mass/molarmass is 30/46 0.652 1 mole OCCUPIES 22.414L 0.652 mole occupies xL Crossmultiplying x= 22.414 0.652 =14.61L

Answer»

Explanation:

NO2 is the OXIDE with nitrogen in 4 oxidation state

MASS given is 30

MOLARMASS is 14+ 16*2 = 46

no of moless is mass/molarmass

is 30/46

0.652

1 mole OCCUPIES 22.414L

0.652 mole occupies xL

Crossmultiplying

x= 22.414 * 0.652

=14.61L

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