Saved Bookmarks
| 1. |
Volume occupied by one molecules of water (density =1 g cm -3) is....... |
|
Answer» DENSITY of water is approximately 1g/ml Thus 1g of water occupy volume = 1 ml Molar mass of water = 18 g/mol Number of moles of water in 1g = 118 moles = 0.055 moles H2O Now 18 g water CONTAIN = 6.022×1023molecules H2O Thus 1 g water will have = 6.022×102318 MOLECULES H2O = 0.334 ×1023 molecules H2O This shows that 0.334 ×1023 molecules H2O will occupy volume = 1 ml Therefore volume occupied by 1 H2O molecule = 10.334×10−23 = 2.99 ×10-23 ml Thus volume occupied by 1 H2O mlecule is 2.99 ×10-23 ml. |
|