Volume occupied by one molecule of water (density=1g cm^-3)

1.	Volume occupied by one molecule of water (density=1g cm^-3)
Answer» Hope it help to u The number of moles in 1 LITRE = 1000 / 18.02 = 55.5 moles. 1 mole of water =6.022 x 10^23 molecules of water, So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. The gram molecular mass of water is 18.02. Thus volume occupied by 1 H2O MOLECULE is 2.99 ×10-23 ml.

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