1.

Volume occupied by one molecule of water density = 1g cm-1 is

Answer»

Molar MASS of water = 18g
Mass = molar mass /AVOGADRO no.
Mass = 18/6.022 *10 to the POWER 23
= 3 * 10 to the power - 23 (approx)
Volume = mass / density
So, volume = 3*10 to the power - 23/1 g/cm
= 3* 10 to the power - 23


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