Viscous force acting between two layers of liquid having area A and velocity gradient (Deltav)/(Deltaz) is given by F = etaA(Deltav)/(Deltaz) . Find dimension of eta.

Viscous force acting between two layers of liquid having area A and ve

1.	Viscous force acting between two layers of liquid having area A and velocity gradient (Deltav)/(Deltaz) is given by F = etaA(Deltav)/(Deltaz) . Find dimension of eta.
Answer» `M^(1)L^(-2)T^(-2)` `M^(0)L^(0)T^(0)` `M^(1)L^(-1)T^(-1)` `M^(1)L^(2)T^(-2)` Solution :`F= ETAA(Deltav)/(DELTAZ) "" DeltaZ`= distance `:. ETA=(FDeltav)/(ADeltaz) "" DeltaV`= velocity `:.[eta]=([F][Deltaz])/([A][Deltav])` `=((M^(1)L^(1)T^(-2))(M^(0)L^(1)T^(0)))/((M^(0)L^(2)T^(0))(M^(0)L^(1)T^(-1)))` `=M^(1)L^(-1)T^(-1)`