Vii) A wire of mild steel as initial length 1.5mand diameter 0.60mm ge

1.	Vii) A wire of mild steel as initial length 1.5mand diameter 0.60mm gets extended byHE 6.3 mm when a certain force is applied toit. If Young's modulus of mild steel is 2.1x 1011 N/m², calculate force applied.[Ans: 250N]
Answer» Answer: 250 N Explanation: Use YOUNG's modulus formula Y = FL/(AE) Where, Y = Young's modulus F = Force acting on wire L = Length of wire A = Area of CROSS section of wire e = Change in length (elongation) From above formula F = YAe / L = Y(πr²)e/L = [2.1 × 10¹¹ N/m² × 3.14 × (0.60/2 × 10^-3 m)² × 6.3 × 10^-3 m ]/ (1.5 m) ≈ 250 N

Vii) A wire of mild steel as initial length 1.5mand diameter 0.60mm gets extended byHE 6.3 mm when a certain force is applied toit. If Young's modulus of mild steel is 2.1x 1011 N/m², calculate force applied.[Ans: 250N]

Answer»

Answer:

250 N

Explanation:

Use YOUNG's modulus formula

Y = FL/(AE)

Where,

Y = Young's modulus
F = Force acting on wire
L = Length of wire
A = Area of CROSS section of wire
e = Change in length (elongation)

From above formula

F = YAe / L

= Y(πr²)e/L

= [2.1 × 10¹¹ N/m² × 3.14 × (0.60/2 × 10^-3 m)² × 6.3 × 10^-3 m ]/ (1.5 m)

≈ 250 N

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Vii) A wire of mild steel as initial length 1.5mand diameter 0.60mm gets extended byHE 6.3 mm when a certain force is applied toit. If Young's modulus of mild steel is 2.1x 1011 N/m², calculate force applied.[Ans: 250N]​

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Vii) A wire of mild steel as initial length 1.5mand diameter 0.60mm gets extended byHE 6.3 mm when a certain force is applied toit. If Young's modulus of mild steel is 2.1x 1011 N/m², calculate force applied.[Ans: 250N]