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Vii.A compound forms hcp structure.Number of octahedral and tetrhedralvoids in 0.5 mole 6f substance isrespectivelya. 3.011*1023, 6.022x1023b. 6.022x1023, 3.011*1023c. 4.011x1023, 2.011x1023d. 6.011x1023, 12.022x1023 |
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Answer» Explanation: Number of close-packed PARTICLES = 0.5×6.022×1023= 3.011×1023 Therefore, number of OCTAHEDRAL voids = 3.011×1023 And, number of tetrahedral voids = 2×3.011×1023= 6.022×1023 Therefore, total number of voids = 3.011×1023+ 6.022×1023= 9.033×1023 |
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