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Vibrating tuning fork of frequency v is placed near the open end of a long cylindrical tube. The tube has a side opening and is fitted with a movable reflecting piston. As the piston is moved through 8.75 cm, the intensity of sound changes from a maximum to minimum, if the speed of sound is 350 m/s. Then v is

Answer»

500 HZ
1000 Hz
2000 Hz
4000 Hz

Solution :When the piston is moved through a DISTANCE of 8.75 cm, the PATH difference produced is `2 xx 8.75 cm = 17.5 cm`. This must be equal to `lambda/2` for changes from maximum to MINIMUM.
`therefore lambda/2 = 17.5 cm, lambda = 35 cm = 0.35 m`
`v = vlambda`
`therefore v =v/lambda = 350/(0.35) = 1000 Hz`


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