(vi) Five years hence, the age of Jacob will be three times that of hi

1.	(vi) Five years hence, the age of Jacob will be three times that of his son. Five yago, Jacob's age was seven times that of his son. What are their present agesears
Answer» Let us assumeJacob’s current age is x his son’s current age is y Five years hence, Jacob’s age = x + 5 his son’s age = y + 5 As per question;x + 5 = 3(y + 5)x + 5 = 3y + 15x = 3y + 15 – 5 = 3y + 10 Five years ago, Jacob’s age = x – 5 his son’s age = y – 5 As per question;x – 5 = 7(y – 5)x – 5 = 7y – 35x = 7y – 35 + 5 = 7y – 30 Substituting the value of x from first equation in this equation, we get3y + 10 = 7y – 303y + 10 + 30 = 7y7y – 3y = 404y = 40y = 10 Substituting the value of y in first equation, we getx = 3y + 10x = 3 x 10 + 10 = 40 Hence, Jacob’s age = 40 years and son’s age = 10 years

(vi) Five years hence, the age of Jacob will be three times that of his son. Five yago, Jacob's age was seven times that of his son. What are their present agesears

Answer»

Let us assumeJacob’s current age is x his son’s current age is y

Five years hence, Jacob’s age = x + 5 his son’s age = y + 5

As per question;x + 5 = 3(y + 5)x + 5 = 3y + 15x = 3y + 15 – 5 = 3y + 10

Five years ago, Jacob’s age = x – 5 his son’s age = y – 5

As per question;x – 5 = 7(y – 5)x – 5 = 7y – 35x = 7y – 35 + 5 = 7y – 30

Substituting the value of x from first equation in this equation, we get3y + 10 = 7y – 303y + 10 + 30 = 7y7y – 3y = 404y = 40y = 10

Substituting the value of y in first equation, we getx = 3y + 10x = 3 x 10 + 10 = 40

Hence, Jacob’s age = 40 years and son’s age = 10 years