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VERY SHORT ANSWER TYPE QUESTIONS-1,2If A, B, C are the angles of a triangle and x = cis A, y = cis B, z = cis C; find the valueof xyz[May 16AP, 15TS, March 18AP, 15AP, April 98 & 94) |
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Answer» Since ABC are angle of triangleA+B+C=180°......(1) Given x=cis A, y=cis B,z=cis C Thus xyz=cis A×cis B×cis C=cis (A+B+C)=cis (180°) from (1)=cos 180°+ i sin 180°=-1+i (0)=-1 Therefore xyz=-1 |
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