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Vertex (0,0), passing through (5,2) and symmetric with respect to y-axis |
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Answer» Let vertex `-=(0,0)` and equation of parabola symmetric to y-axis be `x^(2)=4ay` It passes through the point (5,2). `:." "25=4a(2)` `rArr" "4a=(25)/(2)` Therefore, equation of parabola is `x^(2)=(25)/(2)y`. |
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