1.

Verify whether the proposition [~(p→~q)] v (~p↔q) is a tautology, contradiction or neither.

Answer»

Let [~(p→~q)] = x and (~p↔q) = y

PQ~p~q(p~q)x[~(p~q)]Y(~pq)(x v y)
TTFFFTFT
TFFTTFTT
FTTFTFTT
FFTTTFFF

∴ [~(p→~q)] v (~p↔q) is neither tautology nor contradictia



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