1.

Verify whether the proposition ~(p ∨ q) → (~P ∧ ~q) is a tautology contradiction or neither.

Answer»
pq(p∨ q)~(p∨q)~p~q(~p ∧~q)1→2
TTTFFFFT
TFTFFTFT
FTTFTFFT
FFFTTTTT

From the table we conclude that it is a tautology



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