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Verify that [(729)to the power-5/3]-¹/²=(729) to the power -5/3*(-¹/²) |
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Answer» ((729) 3 −5
) 2 −1
=(729) 3 −5
× 2 −1
Answer - LHS - ({(729)}^{ \frac{ - 5}{3} })^{ \frac{ - 1}{2} }((729) 3 −5
) 2 −1
we \: know \: ({a}^{m} ) ^{N} = {a}^{mn}weknow(a m ) n =a mn
(729) ^{ \frac{5}{6} }(729) 6 5
729 = {3}^{6}729=3 6
({3}^{6}) ^{ \frac{5}{6} }(3 6 ) 6 5
{3}^{5} = 2433 5 =243 _____________________________________ RHS - (729) ^{ \frac{ - 5}{3} \times \frac{ - 1}{2} }(729) 3 −5
× 2 −1
(729) ^{ \frac{5}{6} }(729) 6 5
729 = {3}^{6}729=3 6
( {3}^{6} ) ^{ \frac{5}{6} }(3 6 ) 6 5
{3}^{5} = 2433 5 =243 Hence : VERIFIED : LHS = RHS . |
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