Verify (a+b)+c=a+(b+c) for a=5/6, b=-1/3, c=-3/4

1.	Verify (a+b)+c=a+(b+c) for a=5/6, b=-1/3, c=-3/4
Answer» $\huge{ \green{ \boxed{ \purple{\dag{ \mathfrak{ \orange{ \underline{ \underline{ \blue{answer}}}}}}}}}}$ ${ \mathfrak{ \red{ \underline{ \green{given}}}}}$ $a = \frac{5}{6}$ $b = \frac{ - 1}{3}$ $c = \frac{ - 3}{4}$ $\purple{ \underline{\red{ \mathfrak{to \: verify}}}}$ $(a + b) + c = a + (b + c)$ $\red{\underline{\pink{solution}}}$ $lhs = (a + b) + c$ $\rightarrow ( \frac{5}{6} + \frac{ - 1}{3} )+ \frac{ - 3}{4}$ $\rightarrow \frac{5 - 2}{6} + \frac{ - 3}{4}$ $\rightarrow \frac{3}{6} + \frac{ - 3}{4}$ $\rightarrow \frac{2}{4} + \frac{ - 3}{4}$ $\rightarrow \frac{ - 1}{4}$ $rhs = a + (b + c)$ $\rightarrow \frac{5}{6} + ( \frac{ - 1}{3} + \frac{ - 3}{4} )$ $\rightarrow \frac{5}{6} + \frac{ - 4 - 9}{12}$ $\rightarrow \frac{5}{6} + \frac{ - 13}{12}$ $\rightarrow \frac{10 - 13}{12}$ $\rightarrow \frac{ - 3}{12}$ $\rightarrow \frac{ - 1}{4}$ $therefore$ $lhs = rhs$ $(a + b) + c = a + (b + c)$

Answer»

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