1.

Velocity vectors of three masses 2 kg, 1 kg and 3 kg are vecv_1=(hati-2hatj+hatk)m/s, vecv_2=(2hati+2hatj-hatk)m/sand vecv_3 respectively. If velocity vector of center of mass of the system is zero then value of vecv_3 will be

Answer»

`(FRAC{2hati+2hatj-hatk}{3})` m/s
`(frac{-4hati+2hatj-hatk}{3})` m/s
`(frac{2hati+3hatj-hatk}{3})` m/s
`(frac{-2hati+3hatj-hatk}{3})` m/s

Answer :B


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