velocity of a train changes from 20ms to 25 ms,when it accelerates at

1.	velocity of a train changes from 20ms to 25 ms,when it accelerates at a rate of 2ms -2. Find the distance covered by the train.
Answer» ANSWER: using, v2 -U2 = 2as we get Explanation: u= INITIAL velocity 20 m/s v= final velocity 25m/s Acceleration is 2m/s^2 s =distance ? v2 - u2 = 2as we have, (25)2 - (20)2 = 2×2×s 4s = 225 =)s =56.25 m ●Distance covered by the TRAIN is 56.25m

velocity of a train changes from 20ms to 25 ms,when it accelerates at a rate of 2ms -2. Find the distance covered by the train.

Answer»

ANSWER:

using, v2 -U2 = 2as we get

Explanation:

u= INITIAL velocity 20 m/s

v= final velocity 25m/s

Acceleration is 2m/s^2

s =distance ?

v2 - u2 = 2as we have,

(25)2 - (20)2 = 2×2×s

4s = 225

=)s =56.25 m

●Distance covered by the TRAIN is 56.25m

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velocity of a train changes from 20ms to 25 ms,when it accelerates at a rate of 2ms -2. Find the distance covered by the train.​

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velocity of a train changes from 20ms to 25 ms,when it accelerates at a rate of 2ms -2. Find the distance covered by the train.