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Velocity of a train changes from 20ms -1 to 25 ms-1, when it accelerates at a rateof 2ms-2. Find the distance covered by the train. |
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Answer» Answer: 55m Explanation: a=v-u/t t=v-u/a substituting the VALUES,
DISTANCE travelled=ut+ 1/2*at^2 20*2.5+1/2*2*(2.5)^2 =50+5 m =55 m |
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