1.

Velocity of a train changes from 20ms -1 to 25 ms-1, when it accelerates at a rateof 2ms-2. Find the distance covered by the train.​

Answer»

Answer:

55m

Explanation:

a=v-u/t

t=v-u/a

substituting the VALUES,

25-20/2= 2.5 s

DISTANCE travelled=ut+ 1/2*at^2

20*2.5+1/2*2*(2.5)^2

=50+5 m

=55 m



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