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Velocity(m/s) 15The velocity-time graph of a car is shown in theright sideAnswer the following questions.i) Which part of the graph shows acceleratedmotion? Also calculate the acceleration.ii) Which part of the graph shows retardedmotion? Also calculate the retardation.iii) Calculate the distance travelled by the bodyin first 2 seconds of the journey.D2s6time (5) |
| Answer» EXPLANATION:Given graph is a VELOCITY-TIME graph of an OBJECT.In VT graph:1. The SLOPE of the line at a particular time gives the acceleration of the object at that time.2. Area under the graph gives the displacement of the object._______________________________Coming to the questions:1. Part AB is accelerated motion as the slope of the graph(which gives the acceleration) is positive.acceleration = slopeSo acceleration = 1 m/s^22.Part CD is retarded motion as the slope of the graph(which gives the acceleration) is negative.So acceleration = -1 m/s^2Thus retardation is 1 m/s^23.distance of the BODY in first 4 seconds = area under graph from t=0 to t=4sarea under graph from t=0 to t=4s = area of ∆ABE = 1/2 × 4 × 4 = 8mThus distance of the body in first 4 seconds is 8m | |