Vector A has magnitude of 3 units and makes an angle of 30∘ with th

1.	Vector A has magnitude of 3 units and makes an angle of 30∘ with the positive x-axis. Vector B has magnitude of 4 units and makes an angle of 120∘ with the positive x-axis. Find the magnitude of the resultant and the angle that it makes with the positive x-axis. [tan−1(43)=53∘]
Answer» Vector A has magnitude of 3 units and makes an angle of $30^{\circ}$ with the positive x-axis. Vector B has magnitude of 4 units and makes an angle of $120^{\circ}$ with the positive x-axis. Find the magnitude of the resultant and the angle that it makes with the positive x-axis. $[t a n^{- 1} (\frac{4}{3}) = 53^{\circ}]$

Vector A has magnitude of 3 units and makes an angle of 30∘ with the positive x-axis. Vector B has magnitude of 4 units and makes an angle of 120∘ with the positive x-axis. Find the magnitude of the resultant and the angle that it makes with the positive x-axis. [tan−1(43)=53∘]

Answer»

Vector A has magnitude of 3 units and makes an angle of $30^{\circ}$ with the positive x-axis.

Vector B has magnitude of 4 units and makes an angle of $120^{\circ}$ with the positive x-axis.

Find the magnitude of the resultant and the angle that it makes with the positive x-axis.

$[t a n^{- 1} (\frac{4}{3}) = 53^{\circ}]$

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Vector A has magnitude of 3 units and makes an angle of 30∘ with the positive x-axis. Vector B has magnitude of 4 units and makes an angle of 120∘ with the positive x-axis. Find the magnitude of the resultant and the angle that it makes with the positive x-axis. [tan−1(43)=53∘]

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