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`|vec(A)xxvec(B)|^(2)+|vec(A).vec(B)|^(2)=`A. ZeroB. `A^(2)B^(2)`C. `AB`D. `sqrt(AB)` |
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Answer» Correct Answer - B Let `theta` be angle between Vectors `vec(A)` and `vec(B)` `:. |vec(A)xxvec(B)|=AB sin theta` and `|vec(A).vec(B)|= AB cos theta` `|vec(A)xxvec(B)|^(2)= |vec(A).vec(B)|^(2)=(AB sin theta)^(2)+(AB cos theta)^(2)` `=A^(2)B^(2)sin^(2)theta+A^(2)B^(2)cos^(2)theta= A^(2)B^(2)` |
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