1.

Vapour pressure of a moist gas at 100 °C is 750 mm and aqueous tension at that temperature is 10mmThen vapour pressure of the dry gas is(1) 750mm(2) 760mm(3) 740mm(4) 720mm​

Answer»

<P>Answer:

740 mm

Explanation:

Given Vapour pressure of a MOIST gas at 100 °C is 750 mm and aqueous tension at that temperature is 10mm

Then vapour pressure of the dry gas is

Given vapour pressure = 750 mm at temperature = 100 degree Celsius

 Aqueous tension = 10 mm

P (moist gas) = p(dry gas) + aqueous tension

P (dry gas) = p (moist gas) – aqueous tension

P (dry gas) = 750 – 10  

P (dry gas) = 740 mm



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