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Value of tan π/8 |
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Answer» Let Ф = π/82Ф = π/4 tan 2Ф = 1 = 2 tan Ф / [ 1 - tan² Ф ]\xa01 - tan² Ф = 2 tan Фtan² Ф + 2 tan Ф - 1 = 0tan Ф = 1/2 [ -2 +- √(4 +4) ] = -1 +- √2\xa0tan π/8 is > 0 So, tan π/8 = √2 - 1 2-√3 |
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