1.

Value of `sin(37^circ)cos(53^circ)` isA. `(9)/(25)`B. `(12)/(25)`C. `(16)/(25)`D. `(3)/(5)`

Answer» Correct Answer - A
`sin37^(@)xxcos53^(@)=(3)/(5)xx(3)/(5)=(9)/(25)`


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