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`i=(1-ALPHA)`
`i=(1+alpha)`
`i=(1-alpha//2)`
`i=(1+alpha//2)`

Solution :`2C_(6)H_(5)COOHhArr(C_(6)H_(5)COOH)_(2)`
For association,
`alpha=((i-1))/((1//n-1))=((i-1))/((1//2-1))`
`-alpha//2=i-1or i=(1-alpha//2)`


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